Illustrate why, for iid random variables, the mean and variance of their sum are easier to calculate.
The idea
The iid assumption makes the moments of a sum easy. Suppose X1 to Xn are iid with mean μ and variance σ², and let S be their sum. Whatever the dependence between the variables, the mean of their sum follows from linearity: Mean = nμ. With independence every covariance term is zero, and with identical distribution all n variances equal σ², so the sum has Variance = nσ². Taking the square root gives the standard deviation of the sum. This is why risk scales with the square root of time: SD = σ × √n. Dividing the sum by n gives the sample mean, and division by n divides the variance by n², so the sample mean has Variance = σ² ÷ n. Do not scale a standard deviation by n, and do not add standard deviations. If the observations share a correlation ρ, the variance of S gains n(n − 1)ρσ², so the iid shortcut can badly understate risk.
Formulas
Variance of a sum of n iid variables
Var(S) = n × σ²
- n
- the number of variables in the sum
- σ
- the standard deviation of each variable
Needs independence and identical distribution. The standard deviation is σ × √n, so do not scale σ by n or add standard deviations.
Variance of a sum with a common correlation
Var(S) = n × σ² + n × (n − 1) × ρ × σ²
- n
- the number of variables in the sum
- σ
- the standard deviation of each variable
- ρ
- the correlation between every pair
Use when the variables are identically distributed but correlated. With positive ρ the iid shortcut badly understates the risk.
A practice question
Twenty daily returns are iid, each with mean 0.05 percent and standard deviation 2 percent. What is the standard deviation of the 20-day total return?
- 40.00 percentWhy not: Multiplies the standard deviation by n instead of sqrt(n).
- 80.00 percentWhy not: Reports the variance of the total (80) as if it were the standard deviation.
- 0.45 percentWhy not: Divides by sqrt(n), which is the standard deviation of the average, not of the sum.
- 8.94 percent - correct
Var(sum) = n sigma² = 20 x 4 = 80, so SD(sum) = sqrt(80) = 8.94 percent. The mean of the total is 20 x 0.05 = 1.00 percent.
A harder one
Daily P&L is iid with mean zero and standard deviation 1.2 percent. Using the normal quantile 2.326 for 99 percent confidence, what is the 10-day VaR as a percentage of portfolio value?
- 27.91 percentWhy not: Scales the daily volatility by 10 instead of the square root of 10.
- 2.79 percentWhy not: Reports the one-day VaR without scaling to the 10-day horizon.
- 33.49 percentWhy not: Uses the 10-day variance (1.44 x 10 = 14.4) in place of the standard deviation.
- 8.83 percent - correct
For iid daily P&L, the 10-day standard deviation is 1.2 x sqrt(10) = 3.79 percent and the mean is zero. VaR = 2.326 x 3.79 = 8.83 percent.
The hardest tier
Daily returns are iid with mean 0.04 percent and standard deviation 1.5 percent. Treat the 100-day cumulative return (the sum of daily returns) as approximately normal. What is the probability that it is below -20 percent?
- 5.5 percent - correct
- 9.1 percentWhy not: Ignores the 100-day mean of +4 percent and centres the distribution at zero.
- 43.6 percentWhy not: Scales the standard deviation by n = 100 (150 percent) instead of by sqrt(100) = 10 (giving 15 percent).
- 14.3 percentWhy not: Subtracts the mean with the wrong sign, effectively centring the distribution at -4 percent.
Mean = 100 x 0.04 = 4 percent; SD = 1.5 x sqrt(100) = 15 percent. z = (-20 - 4)/15 = -1.60, so the probability is about 5.5 percent.
In the app: 6 practice questions on this outcome, spaced review that brings it back before you forget it.
Start free →More in Multivariate Random Variables
- Express a probability mass function through a probability matrix and explain how this works.
- From a discrete bivariate random variable, obtain both its marginal and its conditional distributions.
- Describe the way an expected value of a function is obtained for a discrete bivariate random variable.
- Give the definition of covariance and say what quantity it captures.
- Describe how covariance and correlation of two random variables relate to each other and to whether the variables are independent.
- Show, with examples, what happens to the covariance and correlation of two random variables when linear transformations are applied to them.
- Find the variance when two random variables are combined using weights.
- For a bivariate random variable, compute the expected value of one of its components given the other.
- Identify what makes a sequence of random variables independent and identically distributed (iid).